I wouldn't normally think so, but then I would never expect a 7805 to be killed by reverse dump from the 5v 10uF on it's output. If it had 1000uF on the output and someone shorted the Vin pin to ground then ok, but that is not happening here.spikes maybe a good point, but 22V is not enough to kill your 7805, right?
Yes 200mA is too much,I thought you are using the mcu for only switching purpose.Anyway a 10 ohms 1/2 watt or 15 ohms 1 watt will do.So help me out with calculating the power dissipated in that 47 Ohm resistor. Assume max of 200mA for circuit (PIC, status LED, etc.)
So voltage drop would be: .2 * 47 = 9.4V. Something must be wrong because I need at least 7 to run the 7805.
yeah, good point. I never managed to kill my 7805...I wouldn't normally think so, but then I would never expect a 7805 to be killed by reverse dump from the 5v 10uF on it's output.
Maybe with a tantalum cap? I just grabbed my ESR meter and tested a handful of 10uF 16v electros, they were all about 1.5 ohms ESR, at low current (couple mA) and I expect MUCH more than 1.5 ohms at higher currents. But even if at 1.5 ohms worst case, to me that sounds more like 5v/1.5 = 3A (and probably MUCH less) and that is only if you can instantaneously short the input Vin.Just for the record. I found this in the LM117 datasheet by coincidence:
"When external capacitors are used with any IC regulator it is sometimes necessary to add protection diodes to prevent the capacitors from discharging through low current points into the regulator. Most 10 μF capacitors have low enough internal series resistance to deliver 20A spikes when shorted. Although the surge is short, there is enough energy to damage
parts of the IC."
...
I think you're right. That's pretty cool. I've been working on driving that panel regulation; on and off for quite a while. This is fewer parts, less RDSon, more efficient, everything's better. I'll give it a try. Although it probably doesn't belong in this 7805 thread. I'll start a new one.THE_RB said:Russ, the NFET will work fine now you have the FET source pin at ground! Before you had the FET placed between 12v battery and solar panel +, so an NFET would have been very hard to drive there. Now it is easy.
With the circuit you just posted, just swap the FET D and S and replace the part with an NFET. And put that resistor to battery 12v.