circuit percentage

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Joined Sep 5, 2011
48
Is this true?
In a series circuit with only 4 resistors.
R4 resistance percentage is equal to its voltage drop percentage.

\(R_4/R_T=E_4/E_T\)

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Thread Starter

logmode

Joined Sep 5, 2011
48
Thank you,
so then this is also true .

\((R_2/R_T)E_T=E_2\)

and

\((E_2/E_T)R_T=R_2\)

Are there all kinds of hand outs on these formulas?

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