# Circuit I proplem

#### tinhnho

Joined Aug 31, 2004
34
hi everyone

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Joined Jan 19, 2004
220
if yes just msg back and i'll give you the detailed explaination

#### tinhnho

Joined Aug 31, 2004
34
CAN YOU PLEASE TELL THE DETAIL HOW TO GET THAT ANSWER ?THANKS ALOT

Joined Jan 19, 2004
220
check out this attachment
pm me if u have any further doubts

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#### tinhnho

Joined Aug 31, 2004
34
thanks alot for the answer, i just wonder how do you get resistance equal 12 ohm ? . Follow your picture which u drawn If i add resistor 1,2,3 to gether by parallel then it equal .333 ohm,the same with resistor 4,5,6 i have .333 ohm. For the branh with 6 resistor i have 6 ohm if add them togehter bye series: .333 +.333 + 6 = 6.666 ohm than it isn't equal 12 ohm like you said .i am not sure that i was right or wrong , if i did wrong just let me know. thanks

Joined Jan 19, 2004
220
yup sorry my calculations are wrong
the resistors of 3 add to give .3333
and the 6 resistor set gives .1667
so the net comes to .1667+.6666=.83333 ohms
pls check my calc again and let me know

#### tinhnho

Joined Aug 31, 2004
34
so the current Is = 1/.83333= 1.2A ? -->i think this may be the final answer