Circuit Analysis with Transformer

Discussion in 'Homework Help' started by Robert.Adams, Sep 7, 2010.

  1. Robert.Adams

    Thread Starter Active Member

    Feb 16, 2010
    I have been working on the attached circuit and I still differ quite a bit from the answer found on the key.

    My method has been to simplify the load on the right side of the transformer (simplifies to 27.561 + 8.04878j) and then reduce it to account for the transformer (1/9th of the value comes to 3.06233 + 0.894309j).

    From here I add in the 50 ohm resistor and come to a total load resistance of 53.0623 + 0.894309j.

    Dividing this into the voltage source should yield I1. This comes out to be .16475 + .0914521j A. (188.4mA at 29.03 degrees polar).

    The key says the answer should be 175.7mA at 27.9 degrees. Where did I go wrong?
    Last edited: Sep 7, 2010
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    I agree with your answer for I1.
  3. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    The dot & sign conventions marked on the transformer are a little confusing.
  4. Sparkysea

    New Member

    Sep 8, 2010
    I also think you answer for I1 is right.Maybe there is sonething wrong with the key.