Circuit analysis with impedance and laplace

Discussion in 'Homework Help' started by count_volta, Mar 23, 2009.

  1. count_volta

    Thread Starter Active Member

    Feb 4, 2009
    Hello, I need some help on a laplace circuit problem. Here is the circuit


    As you see I added a 10 volt voltage source to represent the initial charge on the capacitor. Then I drew the equivalent laplace circuit representing the impedance of the capacitor and inductor in terms of S.

    The object here is to find the current I(t) in the mesh.

    So I write KVL.


    Now to guess at the solution, I check the poles by setting the denominator = 0.

    I get the following. S1= -200 plus 400 j S2= -200 minus 400 j

    So the solution should be of the form A e^-200t sin(400t) + B e^-200t cos(400t) or so I remember from differential equations class.

    So now I need to do partial fractions. Okay in my book I have this equation.


    My question is, how do I use that equation or ANYTHING ELSE to get the inverse laplace of my expression for i(s) above?

    The book says the answer is

    i(t)= -1/40 e^-200t *sin(400t)

    So I know for sure that my expression for i(s) is correct. How do I get i(t) though. Please help. I am having real trouble with complex conjugate pairs in laplace circuits.
  2. Ratch

    New Member

    Mar 20, 2007

    You need to use the step voltage transform of -10/s on the right side of your equation.

  3. count_volta

    Thread Starter Active Member

    Feb 4, 2009
    Ohhh yes thats right. Laplace of 10 volts is 10/s.

    Slaps self. Thanks :D