I'm having a hard time finding V2 in terms of I2. I've tried various forms of KCL and KVL but I can't seem to find the right answer. I hope someone can enlighten me.
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My node equation is:\(I_2 = \frac{V_22V_x}{2} + \frac{V_2}{5} = \frac{V_22\frac{V_2}{4}}{2} + \frac{V_2}{5} = 0.45V_2\)
\(Z_{22} = \frac{V_2}{I_2} = \frac{V_2}{0.45V_2} = 2.222\)
This is clearly wrong since the answer is supposed to be 1.111 ohm.
by Luke James
by Jake Hertz
by Jake Hertz
by Luke James