it is very basic, only how would it charge to 12V if there is no potential difference. (6V on one end and 6V on the other). Best examples are found by looking at power supplies - capacitors are used as voltage multiplier.
No, he is correct. A simple diode, either Schottky or Germanium, to prevent the 12V on the capacitor from discharging would be beneficial, at the loss of some voltage.
The OP is charging the capacitor to 6V, then putting the 6V in series with the power supply. This will result in a short pulse, as the cap discharges through the power supply.
Here is a practical application of such a setup...