Discussion in 'Homework Help' started by Steve1992, Apr 30, 2011.
Is this an example of the principle of a charge pump?
it is very basic, only how would it charge to 12V if there is no potential difference. (6V on one end and 6V on the other). Best examples are found by looking at power supplies - capacitors are used as voltage multiplier.
I think that the lower left power supply is meant to be -6V, a minor typo.
No, he is correct. A simple diode, either Schottky or Germanium, to prevent the 12V on the capacitor from discharging would be beneficial, at the loss of some voltage.
The OP is charging the capacitor to 6V, then putting the 6V in series with the power supply. This will result in a short pulse, as the cap discharges through the power supply.
Here is a practical application of such a setup...
CMOS 555 Long Duration Blue LED Flasher
The circuit shown is the basic(very basic) principal behind a 'high side' mosfet driver.
Ok, now I see it. Thanks for that, Bill.