Hello,

I would like to know if I am understanding this correctly.

Charge in a cap is directly proportional to the voltage across it.

So if thats the case, if 100V is across a cap storing 100uc, when the voltage across the cap is doubled to 200V, then the charge in the cap is doubled to 200uc.

If this is true, then the capacitance is Q/V=> 200uc/200V=1uF

Please clarify if I am wrong on something. Thanks!

 

You've got it right.

 

electronicsstudent09,

Charge in a cap is directly proportional to the voltage across it.

No, the imbalance of charge is directly proportional to the voltage across it. Whatever charge you accumulate on one plate of the capacitor is depleted on the other plate for a net charge of zero. This imbalance of charge causes a voltage to form. The ratio of charge imbalance to voltage is capacitance.

Ratch