Figure 2-12 shows a cascaded timer circuit that uses two separate
555 timer chips. In this circuit, both the 555 timer chips are configured
in monostable mode, much like the circuit in Figure 2-3. The time interval for
the first 555 is controlled by R1 and C1. For the second 555, the interval is
controlled by R2 and C2. You can choose whatever values you want for these
components to achieve whatever time intervals suit your fancy.
The first 555 chip is triggered when SW1 is depressed, taking pin 2 to ground.
This action takes the output on pin 3 to high, which lights LED1. Notice,
however, that pin 3 of the first 555 is connected through a small capacitor to
the trigger input of the second 555. As soon as the time interval expires on
the first 555, its output goes low, which turns off LED1 and at the same time
triggers the second 555, which in turn lights up LED2. LED2 stays lit until C2
charges, and then it goes out. The circuit then waits to be triggered again by
a press of the switch.
The problem I have is that I don't understand how input 2 (trigger) of 555 (2) can get low as soon as output 3 of 555 (1) expires. The capacitor indicated with red arrow is in series with input (2).
555 timer chips. In this circuit, both the 555 timer chips are configured
in monostable mode, much like the circuit in Figure 2-3. The time interval for
the first 555 is controlled by R1 and C1. For the second 555, the interval is
controlled by R2 and C2. You can choose whatever values you want for these
components to achieve whatever time intervals suit your fancy.
The first 555 chip is triggered when SW1 is depressed, taking pin 2 to ground.
This action takes the output on pin 3 to high, which lights LED1. Notice,
however, that pin 3 of the first 555 is connected through a small capacitor to
the trigger input of the second 555. As soon as the time interval expires on
the first 555, its output goes low, which turns off LED1 and at the same time
triggers the second 555, which in turn lights up LED2. LED2 stays lit until C2
charges, and then it goes out. The circuit then waits to be triggered again by
a press of the switch.
The problem I have is that I don't understand how input 2 (trigger) of 555 (2) can get low as soon as output 3 of 555 (1) expires. The capacitor indicated with red arrow is in series with input (2).
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