capacitor

MrChips

Joined Oct 2, 2009
30,802
Not quite. Charge, voltage and capacitance are all inter-related, much like Ohm's Law.


\(V = \frac{Q}{C}\)

Hence the energy stored in a capacitor of a given capacitance C can can be determined entirely from charge Q,

\(E = \frac{1}{2}\frac{Q^2}{C} \)

or from voltage V,

\(E = \frac{1}{2}CV^2 \)
 

DerStrom8

Joined Feb 20, 2011
2,390
Not quite. Charge, voltage and capacitance are all inter-related, much like Ohm's Law.


\(V = \frac{Q}{C}\)

Hence the energy stored in a capacitor of a given capacitance C can can be determined entirely from charge Q,

\(E = \frac{1}{2}\frac{Q^2}{C} \)

or from voltage V,

\(E = \frac{1}{2}CV^2 \)
Yup, I remember seeing that before, specifically the last one. Not really sure what I was thinking.

Guess it's been too long since I did any math relating to electronics! :eek::p
 
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