I feel fairly comfortable with this question, however I have some concerns about the signs for certain values throughout the problem.
First concern, the negative sign on the angle θ from the PF, does it matter that I put it to 36.87°?
The voltage across the load sits at 0°, and since the PF is lagging, the current should be behind the voltage, hence my reason for the negative sign.
Note that I did this for the angle for the new PF in part 2), which brings my next question.
Since I made θ and α negative angles, my reactive portions of the power come out as negative, which is okay but how do I get rid of the j in the impeadance for the capacitor in the expression,
\(Q_{cap} = V^{2}(j\omega C)\)
Are we only considering the magnitude?
If that's the case then the j disapeers, but how do I get rid of the negative on the LHS?
Is this the right way of thinking about it?
EDIT: I realized I've made mistakes in the first portion of the question.
First concern, the negative sign on the angle θ from the PF, does it matter that I put it to 36.87°?
The voltage across the load sits at 0°, and since the PF is lagging, the current should be behind the voltage, hence my reason for the negative sign.
Note that I did this for the angle for the new PF in part 2), which brings my next question.
Since I made θ and α negative angles, my reactive portions of the power come out as negative, which is okay but how do I get rid of the j in the impeadance for the capacitor in the expression,
\(Q_{cap} = V^{2}(j\omega C)\)
Are we only considering the magnitude?
If that's the case then the j disapeers, but how do I get rid of the negative on the LHS?
Is this the right way of thinking about it?
EDIT: I realized I've made mistakes in the first portion of the question.
Attachments

16.4 KB Views: 10

50.4 KB Views: 10
Last edited: