can you help me please ?

jegues

Joined Sep 13, 2010
733
hi guys , I am having difficulty in solving this circuit by transformation

can you show me the steps and how to find Vx(voltage)
Start off by transforming the two voltage sources and series resistances on the left hand side of the circuit into current sources with parallel resistances.

After doing so you should be able to make a parallel combination of the resistances and current sources.

That should be enough to get you started!
 

jegues

Joined Sep 13, 2010
733
i tried but i didn't find the right answer (48V)

could you explain more plz
If you show us your attempt it makes it alot easier for us to help you.

I'll get you started with the leftmost voltage source and resistance.

Applying ohms law we would see a current source of the value,

\(I = \frac{V}{R} = \frac{120V}{20\Omega} = 6A\)

The value of the parallel resistance for the transformed voltage source will be identical to its previous(before being transformed) series resistance.
 

jegues

Joined Sep 13, 2010
733
hi guys , I am having difficulty in solving this circuit by transformation

can you show me the steps and how to find Vx(voltage)
Also, there may be a mistake in the figure you've posted. Usually the positive terminal of a DC voltage source is on the end with the wider "line".

In your figure it seems to be the opposite.
 

steveb

Joined Jul 3, 2008
2,436
yes it is 48v
also as you said the signs should be opposite
So, what did you get for your answer?

I ask because I did it out by two methods. Both answers agreed but it came out less than 48V.

I'm curious if you got the same answer I did.

First I did it using source transformation, and then I checked it using circuit equations. Perhaps there is an error in the schematic, as mentioned above.
 

steveb

Joined Jul 3, 2008
2,436
OK. I just noticed that if you assume that V1 us defined backwards and V2 is correct, the answer is 48v.

Try it that way. EDIT: Ok I see that you did it that way above. Good!
 
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