# Can you guys help me with this Problem (El. Eng.1)

Discussion in 'Homework Help' started by PleaseHelp, Sep 6, 2009.

Sep 6, 2009
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Can you guys help me with this problem I have..?

Its very urgent and any help would be truly appreciated..

Here is the image I tried to make on Paint...

All I need to find out is what ( Ix ) is.. But I do need the solution to it...

Thanx

2. ### ancor New Member

Sep 6, 2009
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is veri easy, made it with node method..
you know the node method???

Sep 6, 2009
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i do not, just started this course and i need this by tomorrow..which is why its so urgent....can you please show me.. like post how to do it or something.. id really appreciate it mate..anything would help..

4. ### Ratch New Member

Mar 20, 2007
1,068
4

OK, the first thing we do is combine the two north parallel 5 ohm resistors into one 2.5 ohm resistor. Then we realize that the 2 amp east branch will have 2 amps existing in it no matter what value the 5 ohm southeast resistance is. So we remove the 5 ohm southeast resistor in series with the 2 amp current source, and replace it with a zero ohm wire. Next we realize that the voltage across the 5 ohm south resistor in parallel with the 6 volt source going to be 6 volts no matter what the resistance value is. So we remove it completely from the circuit. Then we call on our friend Mr Thévenin to change the east branch to a 10 volt source in series with a 5 ohm resistor, and the west side branch to a 4 volt source in series with a 2.5 ohm resistor. Now we sum up the voltage sources around the outside loop. They are starting from the west side and going clockwise 4 volts + 10 volts + 6 volts = 20 volts. Then sum up all the resistances. They are starting from the west and going clockwise 2.5 ohms + 2.5 ohms + 5 ohms = 10 ohms . Therefore, the current around the loop is 2 amps and each of the 2 north resistors has 1 amp of current existing within it.

Ratch

Mar 20, 2007
1,068
4