Each resistor, alongside of each coil, is 1.2 Ohms.

His total amperage is 2.8A, and the voltages on each resistor adjacent to each of his coils are ...

Coil of 11 turns: 8.6V peak amplitude on resistor R2.

Coil of 7 turns: 4.0V peak amplitude on resistor R1.

Doing the math ...

8.6V ÷ sqrt(2) ≈ 6.1V RMS (R2)

4.0V ÷ sqrt(2) ≈ 2.8V RMS (R1)

Doing a little bit of Ohm's Law relationships ...

The voltage of R1 ÷ the resistance of R1 = the current of R1, and likewise for R2. So, ...

6.1V RMS ÷ 1.2Ω ≈ 5.1A (R2)

2.8V RMS ÷ 1.2Ω ≈ 2.3A (R1)

Since his total current is 2.8A, then ...

The currents of R2 + R1 = total current. So, ...

5.1A (R2) + (–2.3A) (R1) = 2.8A of total current outside of the transformer.

Does this mean that with his data, the current on the larger coil must be inverted?

What mechanism of electrodynamic theory makes this

*mandatory*?

Screenshots, follow ...