I've attached the circuit in question.
My objective is to turn on a fan when the temperature reaches a set limit.
The voltage on pin 1 drops from 12V to 3.2V when the set limit is exceeded.
Can I use the 2N3906 (PNP) transistor to activate a small fan (12V/240mA)?
I would appreciate somebody telling me if my approach is correct or where I have gone wrong.
Required current for fan is 240mA or 0.240A.
Beta of transistor is 300. (not sure If Im reading the datasheet correctly here)
Voltage at pin one when limit is exceeded is 3.2V.
Calculation for transistor turn on amperage is calculated as;
0.240A divided by Beta 300 = 0.0008. So 1mA is required at base of transistor to switch fan on.
3.2V - 0.7V = 2.5V.
So, base current is calculated as; 2.5 is divided by 0.001 = 2500 or 2.5K
My objective is to turn on a fan when the temperature reaches a set limit.
The voltage on pin 1 drops from 12V to 3.2V when the set limit is exceeded.
Can I use the 2N3906 (PNP) transistor to activate a small fan (12V/240mA)?
I would appreciate somebody telling me if my approach is correct or where I have gone wrong.
Required current for fan is 240mA or 0.240A.
Beta of transistor is 300. (not sure If Im reading the datasheet correctly here)
Voltage at pin one when limit is exceeded is 3.2V.
Calculation for transistor turn on amperage is calculated as;
0.240A divided by Beta 300 = 0.0008. So 1mA is required at base of transistor to switch fan on.
3.2V - 0.7V = 2.5V.
So, base current is calculated as; 2.5 is divided by 0.001 = 2500 or 2.5K
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