I too am confused. Traditionally the constant c arises due to integration, if so the equation would become:Papabravo said:I'm confused, c does not appear in the function, or am I missing something?
d/dx(ln(x)) / d/dx(x-1) = (1/x) /1 = 1/x evaluated at x = 1 is just 1
To correct the above:Papabravo said:To evaluate the limit of an indeterminate form use L'hopital's rule. Take the derivative of the numerator and the derivative of denominator. Now evaluate that quotient.
so c = 1 is the value of the function which makes the original function continuous.Rich (BB code):d/dx(ln(x)) / d/dx(x-1) = (1/x) /x = 1/x^2 evaluated at x = 1 is just 1
by Robert Keim
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