a) g(t) = 2 + 3cos(100t) + 4cos(100t - 120)

b) h(t) = 2 + 3cos(100t) + 4cos(101t - 120)

I am pretty sure the first one is straight forward since 2 is a constant voltage then the value will just be two the second part would be 3/sqrt(2) and the last part would be 4/sqrt(2) in phase -120 degrees and just add them up if that is correct I believe.

The second part I am kind of lost because I am not sure what to do with the 101t since it is not the same as the 100t.