Hi Chaps
I have just built a circuit based on the XR2066 IC. Basically the circuit is a ring modulator. Now currently it's frequency range is from 3Hz to 5kHz. For my needs this range is excessive and the only portion of the scale that is useful is minute.
What I would Like is a range between 14.5Hz and 42.85Hz. On the data sheet for the chip the math is given as-
1/RC=Hz
Now I do struggle a bit with maths but for the past few hours I have used the existing component values to try and understand the answer and have eventually got what seems to be a set of answers that may be correct. Please believe me when I say I am horrific at math
The capacitor in the circuit is 100nF
The resistor is 2K2
The potentiometer in series with the resistor is 2M2
so the sum for the minimum frequency is -
1÷((2.2e3)×100e−6) = 4.545454545 or 5kHz?
For the maximum frequency -
1÷((2.2×10e6)×100e−6) = 0.000454545 or 5Hz?
I may be calling the minimum and maximum values the wrong way round. But have I understood and executed the math correctly?
If I have then I guess I can work out the values required to get the components that will give me the new range of frequencies.
Thanks for looking
regards
Fenris
I have just built a circuit based on the XR2066 IC. Basically the circuit is a ring modulator. Now currently it's frequency range is from 3Hz to 5kHz. For my needs this range is excessive and the only portion of the scale that is useful is minute.
What I would Like is a range between 14.5Hz and 42.85Hz. On the data sheet for the chip the math is given as-
1/RC=Hz
Now I do struggle a bit with maths but for the past few hours I have used the existing component values to try and understand the answer and have eventually got what seems to be a set of answers that may be correct. Please believe me when I say I am horrific at math
The capacitor in the circuit is 100nF
The resistor is 2K2
The potentiometer in series with the resistor is 2M2
so the sum for the minimum frequency is -
1÷((2.2e3)×100e−6) = 4.545454545 or 5kHz?
For the maximum frequency -
1÷((2.2×10e6)×100e−6) = 0.000454545 or 5Hz?
I may be calling the minimum and maximum values the wrong way round. But have I understood and executed the math correctly?
If I have then I guess I can work out the values required to get the components that will give me the new range of frequencies.
Thanks for looking
regards
Fenris