calculating DC offset

Discussion in 'Math' started by tomshong, Aug 22, 2012.

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  1. tomshong

    Thread Starter Member

    Oct 6, 2011
    Not sure my question pertain to just math. Think there's some analog question as well.

    I was reading this paper on direct conversion receiver, and there's a part on the math of calculating the DC offset due to self mixing that I am a little confused about.

    Refer to 4th paragraph in page 3 of the paper.

    1) It says the LO has a Vpp of 0.63v (0dBm in a 50 ohm system)... how does a 0.63v translate to a 0 dBm in a 50 ohm system?

    2) following the rest of the paragraph. Suppose I start off with 0 dBm, then it goes down to -60dBm due to the attenuation, then the LNA/mixer gain of 30dB put it at -30dBm at the output of the mixer? how does -30dBm at the output translate to 10mV?

    3) with a 10mV dc component at the input into an amplifier, how would that drive the amplifier into saturation?
  2. bertus


    Apr 5, 2008

    I have moved the answers to your other thread with the same subject:
    calculating DC offset

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