Ok, I have had a difficult time understanding how one would calculate current flow on the secondary side of a transformer.

In a transformer which has a turns ratio of 1:10, 12V and 2 amps is applied to the primary, meaning the seondary has 120V and .2 Amps with no load.

The secondary circuit has an inductor whose inductive reactance equals 100 Ohms and a series resistance which equals 5000 Ohms.

How do I calculate the current in the secondary side of this circuit?

is it just 120V divided by 5,100 Ohms=23mA?

In a transformer which has a turns ratio of 1:10, 12V and 2 amps is applied to the primary, meaning the seondary has 120V and .2 Amps with no load.

The secondary circuit has an inductor whose inductive reactance equals 100 Ohms and a series resistance which equals 5000 Ohms.

How do I calculate the current in the secondary side of this circuit?

is it just 120V divided by 5,100 Ohms=23mA?

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