It's not just one single LED; it's the sum of the Vf's of all the LEDs in a string.Sarge,
I understand what you wanted me to do now.
At 20ma, I measure 3.18 V across one of my "dim" LEDs. I am measuring 3.16 across one of the "bright" LEDs.
One or more of the LEDs in the bright string has a very low VF, and one or more of the LEDs in the dim string has a very high Vf.
The low Vf and high Vf LEDs are "problem children". What you can often do is put one low Vf and one high Vf in a string, and the two will even each other out.And here is something curious.
With one of the "bright" LEDs disconnected, the whole panel lights starts to light around 8.7 VDC.
I'd bet I could do better if I disconnected those other "bright" LEDs. I would be willing to do that or replace them if it meant light the whole panel at a lower voltage.
For example, if you have three LEDs that have exactly 3.2v across each in series @ 20mA, then the total voltage drop is 9.6v.
However, if one Vf is quite low, like 2.9v, the total drop across the string will be 9.3v at 20mA.
If one Vf is quite high, like around 3.5v, the total Vf will be significantly higher.
But if you match up one that has a low Vf (2.9v) with the high Vf LED (3.5v), you can still get 2.9+3.5+3.2 = 9.6v.