Hi,

As part of my project, I'm trying to integrate the following buck converter into my design (DC to DC voltage converter).

Could you please indicate its main principles of operation?

Is it correct to say that large Duty Cycle of the CMP signal produces high voltage (close to VBAT Port's voltage) at the output? (Load port)

Thank you very much.

 

Could anyone help please?

 

I designed buck converters for about 30 years, and I have absolutely no idea what that drawing is supposed to be.

As an approximation, the output voltage is the input voltage multiplied times the top switch's duty cycle (neglecting voltage drops across switch elements).

If you want to understand how a buck works, here is an app note on it:

 

I designed buck converters for about 30 years, and I have absolutely no idea what that drawing is supposed to be.

I have come across some stuff over the years, however until now I never saw an OpAmp with 100 GHz bandwidth.

Moreover, buck converters can be had a lot cheaper using simulation software (for instance LTSpice).

The information where he obtained this particular design is absent.
The information what software he is using is absent.
The information what modification or experiments he already made is absent.

But nonetheless, the flyback diode is already substituted with a MOSFET. I am impressed.

 

I have come across some stuff over the years, however until now I never saw an OpAmp with 100 GHz bandwidth.

I think Radio Shack sells them.....