Buck Converter Design

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Discussion in 'Homework Help' started by skymeat, Oct 28, 2013.

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  1. Oct 28, 2013 #1
    skymeat

    Thread Starter New Member

    Oct 28, 2013
    1
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    I having some trouble determining the inductor value for a buck converter. Here are the design specifications:
    Vin: 12.0V
    Vout: 5.0V
    Regulation: +/- 25mV
    Load: 20W
    Switching Freq: 200 kHz

    Here is my work thus far:
    R = \frac{5^{2}}{20} = 1.25Ω
    D = Vo/Vin = 5/12 = 0.416667
    I_L = Vo/R = 5/1.25 = 4A

    How do I find ΔIL so I can use the following equation to find my L value?
    ΔIL = -(1/L)*Vout * (1-D) * T
     
    #1 Reply
  2. Oct 28, 2013 #2
    Jony130

    AAC Fanatic!

    Feb 17, 2009
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