need help simplifying
1. (A+B')' + AB
2. A'B + AB

 

If I remember, the answers to both questions is "B".

for #2, you take the B and the rest of the equation goes in brackets, so you get: B(A' + A)

applying logic, the only two cases you get when you try to simplify is B(1 + 0) and B(0 + 1)

in an "OR" situation, if at least one input is a logic high ("1"), then the output is a logic high.

given that, we get: B(1)
and based on ridiculously-simple logic: anything * 1 = anything.

so therefore, we get: B.

 

1. (a+b')' + Ab = A'b'' + Ab (since (a+b)' = A'b')
= A'b + Ab
= (a' + A) B
= 1.b = B
2. Refer From The Second Step Of 1.