I read your tutorial and am still having trouble with Boolean simplification.

What I am going to do is write out my attempts at simplification of several problems and ask for any input on A. whether I got the correct answer and if not where I went wrong. and B. if there is a simpler logic. Two of these are homework problems the rest are just problems I am using to increase my knowledge of proper boolean process

**Problem number one:**

A'B + AB + A'B'

**READ AS WITH MY Logic A not and B OR A and B OR A not and B not**

((A + B') (A' + B') ( A + B))'

**Here I applied involution**

(A + B')'

**After (A' + B') cancels (A + B)**

A' + B

**my final answer**

**Problem number two:**

AB + A'B + AB'

((A+B)' (A'+B)' (A+B')')' involution

((A'+B') (A+B') (A'+B))'

(A'+B')' after cancelation

A + B My final answer

In the above two problems I tried to adopt my logic from an internet example that used a k map.... but now my second inverse seems wrong according to my professor's lecture notes

Ok the tough ones:

**Problem number three:**

(A + B) (A' + C) (B' + C')

( (AB)' +(A'C)' +(B'C')' )'

( A'B' + AC' + BC )'

This is the point that I get stuck! every attempt to simplify further leads to everything cancelling out everything else!

my final answer is...

AB + A'C + B'C'

If the consensus theorem applies - (A + B)(A' + C)(B + C) = (A + B)(A' + C) - or - A B + A'C + BC = AB +A'C - how would I apply it? it seems to me in my example all the variables cancel each other out ie. A to A', C to C' , B to B'

**Problem number four:**

A'B + AB'

( (A + B') (A' + B) )'

( AA' + AB + B'A' + B'B)'

( 0 + AB + B'A' + 0 )'

( AB + A'B' )'

(A' + B') ( A + B) my final answer

**Problem number five:**

(a+b) + c

c + (a + b)'

which could be ....

c + a' + b'

or

( (c)' (a'b')')'

(c'ab)'

c+a'+b' My final answer.

Ok, I realize I probably got most of these problems wrong so any help would be much appreciated. I did read the tutorial and will look at it again. My problem is the examples seem to make sense but my application is off.