Im having trouble with these problems, any help is appreciated.

h= ab'+bc'd'+abc'd+bc
= ab'(c+c') + b(d+cd') + abc'd
= ab' + bd + bc + abc'd
= b(c+ac'd) + ab' + bd
= bc + abd + ab' + bd
= bc + ad + ab' + bd

This is where Im stuck.
should be 3 terms with 6 literals


h = ab' + bc'd' + abc'd + bc
= bc'(d' + ad) + ab' + bc
= bc'd' + abc' + ab' + bc
= bc + bd' + ab' + ac'

should be 3 terms with 5 literals

 

I don't really see what the difference is between the two equations. By mapping the first I get a+a'bc+a'bd' which could be rewritten as a+a'b(c+d')