# Boolean equations

Discussion in 'Math' started by anytime, Feb 15, 2011.

1. ### anytime Thread Starter New Member

Feb 15, 2011
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0
HI GUYS I HAVE A PROBLEM HERE , IT SAYS
CONTRUCT A LOGIC CIRCUIT FROM THE FOLLOWING BOOLEAN EQUATION, AND COMPLETE TJE TRUTH TABLE :
f(xyz)=y.z'+xz

2. ### Georacer Moderator

Nov 25, 2009
5,151
1,266
You can start from the truth table.

Construct it as follows:
Make a table with 4 columns and 8 rows. The columns are x,y,z and F, that is, the inputs and the output of your expression. The rows are as many as the possible combinations of the inputs, that is, 2^3=8.
Each row represents a number from 0 to 7, and should be numbered with increasing order. For example, row number 0 has x=0,y=0 and z=0. Row number 5 has x=1, y=0 and z=1 (101 is the binary 5).
The last column should be filled with the result f(x,y,z) that corresponds to each row.

Can you post the build and post the truth table, before we move on to the circuit?

3. ### anytime Thread Starter New Member

Feb 15, 2011
4
0
hey GEORACER thnx 4 ur help .but could u please do me a favour by demonstrating to me that how am i going to construct that truth table

Nov 25, 2009
5,151
1,266