Boolean equations

Discussion in 'Math' started by kallen, Jun 2, 2004.

  1. kallen

    Thread Starter New Member

    Jun 2, 2004
    I am so confused, can someone pleaase help?

    Prove the identity of each of the following Boolean equations, using algebraic manipulation:

    a) AB + B C' D' + A' B C + C' D = B + C' D

    B) WY + W' Y Z' + WXZ + W' X Y' = WY + W' X Z' + X' Y Z' + X Y' Z

    c) A C' + A' B + B' C + D' = (A' + B' + C' + D')(A + B + C + D')

    The ' is the complement of the variable preceding it. Please help if anyone can.

    Thanks so much!!!!!
  2. susi

    Active Member

    Jun 4, 2004
    hi kallen,

    this is not too much difficult just to apply the Boolean Algebraic functions.I am also doing these things in these days as I have the course (Digital Logic design). I will give u the answer tommorrow.....for now m going to take a sleep zzzzzzzzzz
    shall write ya,
  3. beautifulmind

    New Member

    Mar 5, 2007
    Look at the colors before the equal sign and after it, and see how it is applied in the example.
    if you can visualise this i dont think you'll have a problem understadning and solving the rest. Match the colors and ull unederstand alot.

    X'Y+X =X+Y
    X+X' =1
    Y+1 =1

    A'B + A'BC + BC'D' +C'D
    =B(A+A'C) + C'(BD'+D)
    =B (A+C) + C'(B +D)
    =AB +BC +BC' +C'D
    =AB+B(C+C') + C'D
    =AB+B(1) +C'D
    =B(A+1) + C'D
    =b(1) +C'D
    =B +C'D

    if this is understood let me know so i can continue solving the rest they are quite simple an straight forward if u want me to explain in details also let me know. All the best sile