Boolean Algebra

Thread Starter

BruceBly

Joined Jul 26, 2012
25
Can anyone help me understand this?



I don't understand why the BC turn into a 0. Can someone explain that to me?
 

debjit625

Joined Apr 17, 2010
790
Its already written their, the term BCAB' turns into 0 as for identity AA' = 0 in case of BCAB' the BB' = 0 ,So BCAB' = ACBB' = AC * 0 = 0
You need to know DeMorgan’s theorem and Boolean arithmetic

Good Luck
 
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