boolean algebra

Thread Starter

Jdebeer123

Joined Mar 12, 2011
1
Hi there

with regards to the question Cino had I am also having a bit of trouble.

My effort so far is as follows then I get stuck.Please help

F1 = x + x'(yw)' + w'y
= 1(yw)' + w'y
= 1(y' + w') + w'y
= y' + w' + w'y
=

I cant seem to find any rules that apply to the last one

Also F2 = (y' + x')'
= y + x or would it be double Not's (y'' + x'')


Please help

Thanx

 

justtrying

Joined Mar 9, 2011
439
from your efforts, you can keep factoring = y' + w' + w'y = y'+w'(1+y) - does (1+y) equal anything? But I think you might want to review how you got x + x'(yw)' to reduce to 1(yw)' - it is true that x+x'=1, but that is not what I see in the question, unless you missed the brackets when posting it :)
 
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