Here is my solution:I am having trouble reducing the following probems.
F = AB’CD’ + A’BCD’+AB’C’D+A’BC’D
F = A’BC’+ A’B’C+ AC’D+ ACD’
F = (A′ + BD′ + AD) (B + C′) (A+ B′C)
Any help would be appreciated.
Thanks in advance.
by Gary Elinoff
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