# Boolean algebra (POS) for circuit with NOR gates

Discussion in 'Homework Help' started by pixel1, Apr 17, 2013.

1. ### pixel1 Thread Starter New Member

Apr 13, 2013
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0
Hi all,

I'm trying to determine the correct way to decipher the Boolean expression for the circuit in the attached image. I have gone as far as working it out to be ((((A+B)A'+C)+B') as a product of sums expression. From here, what would be involved with simplifying this expression and circuit, still using only NOR gates? What working/steps need to be taken? I'm getting good at SOP but POS is turning out to be quite challenging :-(

Thanks in advance for any help

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2. ### WBahn Moderator

Mar 31, 2012
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7,109
First off ((((A+B)A'+C)+B') is not POS. Think of the name. A "product" of "sums". That means something of the form:

(a+b+c+d)(a+b')(c'+d')

Second, are you sure that ((((A+B)A'+C)+B') even describes your circuit? This says that if B is LO that the output is HI. Is that true?

Next consider what happens if you apply DeMorgans to the SOP form.

Last edited: Apr 17, 2013