Simplify agebraicly to be sum of 3 terms

(A+B'+C'+D')(B+C+D)(B'+C'+D')(A'+B+C+D)

Simplify the following expressions

(A'C+B+DF')[A+C'+B'+DF']=

(AC+B')(G+F+DE)(AC+B')'=

(X'+Y'Z'+1)(X+Y)(X+Z)=

(A+B'C+1)(B'+C'+BCF)=

PQ(M'N'P'+NR+R'S')R'=

Simplify to obtain a sum of three terms

[A(equivilance)B][CD(exclusiveNOR)B']+ABCD


if you can help with any that would be awesome!
i'm terrible stuck on all of them so any help counts.
thanks in advance!

 

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