Look at this equation:
f = (a + c)*(a' + b)
I solve it by distributing the terms:
f = a'(a + c) + b(a + c)
= aa' + a'c + ab + bc
= a'c + ab + bc --> Resolution
Then i plot it into the Karnaugh map:
* Sorry for the bad drawing
And i get:
f = a'c + ab(from the map)
f = a'c + ab + bc --> (comparing to the resolution by algebra the "bc" term is missing).
I look at the map and i know right away that the "bc" term gets simplified by ther other 2 (regarding that the bold 1's in the map are the "bc" term).
Now i don't know how i can simplify f = a'c + ab + bc to f = a'c + ab using algebra only! How to do it? There's any rule i'm missing in there or what?
f = (a + c)*(a' + b)
I solve it by distributing the terms:
f = a'(a + c) + b(a + c)
= aa' + a'c + ab + bc
= a'c + ab + bc --> Resolution
Then i plot it into the Karnaugh map:
* Sorry for the bad drawing
And i get:
f = a'c + ab(from the map)
f = a'c + ab + bc --> (comparing to the resolution by algebra the "bc" term is missing).
I look at the map and i know right away that the "bc" term gets simplified by ther other 2 (regarding that the bold 1's in the map are the "bc" term).
Now i don't know how i can simplify f = a'c + ab + bc to f = a'c + ab using algebra only! How to do it? There's any rule i'm missing in there or what?
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