Boolean Algebra Help

Discussion in 'Math' started by juanc2719, Mar 20, 2008.

  1. juanc2719

    Thread Starter New Member

    Mar 20, 2008
    I have a project and i dont know how i do this, please if someone can solve only this one with all the steps. i have to simplify this using boolean algebra

    A'B'D + A'BD' + BC'D' + BCD' + AB'C'D + B'CD
  2. Dave

    Retired Moderator

    Nov 17, 2003
    Please do not hijack other members threads. If you have a question start your own thread.

    Firstly, common factors. Secondly, look at using the core Boolean identities.

    Have a go and post up you attempts. From there we can give you feedback and point you in the right direction if need be.

  3. chesart1

    Senior Member

    Jan 23, 2006
    You resolve the problem with the boolean laws.

    If you look carefully at your problem, you will see two terms that can be simplified.
    BC'D' + BCD'

    You know that C + C' = 1

    Therefore first you separate BD' like this...

    BCD' + BC'D' = BD'(C + C')

    And then you equate C+C' to 1

    BD'(C + C') = BD'(1) = BD'

    Use the Booleans laws to resolve the rest of the problem. It may seem difficult at first but as you practice, it will get easier.