We all know that in a BJT, a rise in temperature causes a drop in Vbe and an increase in collector current, when working in the active region. We can verify that in most transistor layouts using Kirchoff's laws. But what about the actual collector current equation: \(I_c=I_s\cdot({e^{\frac{V_{\tiny{BE}}}{nV_{\tiny{T}}}}) \) ? Having in mind that \( V_{\tiny{BE}} \) drops when temperature increases, shouldn't Ic drop too? I know some other variable in the equation must be affected by the temperature, but I don't know which one and how it affects the whole situation. I examined V\(_{\tiny{T}}\) but it doesn't seem to affect Ic enough to compensate for the change of \( V_{\tiny{BE}} \).
Any thoughts? Thanks in advance.
Any thoughts? Thanks in advance.
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