Okay, according to the datasheet (see page 2), the typical forward voltage is 1.8V with a current draw of 1mA per segment.
R_led = (Vcc - V_led) / I_led
Assuming you are still planning to use a 5VDC supply (Vcc), the current-limiting resistor values you want to use will be:
R_led = (5VDC-1.8VDC) / 1mA = 3.2VDC / 0.001A = 3200Ω or 3.2kΩ
You could use two 1.5kΩ in series per segment to get 3kΩ which would be close enough without having to reorder more parts. If you want it dimmer, you could use a 4.7kΩ or 5.1kΩ and see if it is dim enough.
Hope this helps.
No, the current limiting resistors will take care of the voltage difference while protecting the segments from too much current, so the 3.3V regulators are not needed.Will I need a separate voltage for the displays? I have 3.3v regulators.
Not quite. Look at the equation I provided earlier:I think the display uses 1mA (it gives descriptions based on 1mA) so 5v *.001 = 5K ohm resistor correct? Can I use a 5.1K to make the display a bit darker?
R_led = (Vcc - V_led) / I_led
Assuming you are still planning to use a 5VDC supply (Vcc), the current-limiting resistor values you want to use will be:
R_led = (5VDC-1.8VDC) / 1mA = 3.2VDC / 0.001A = 3200Ω or 3.2kΩ
You could use two 1.5kΩ in series per segment to get 3kΩ which would be close enough without having to reorder more parts. If you want it dimmer, you could use a 4.7kΩ or 5.1kΩ and see if it is dim enough.
Hope this helps.