Could someone kindly help me with this assignment. The diode current, i terms of voltaveV, is approximately given by I=I.{exp(eV/kT)-1} where e=1.6^-19 coulomb is the electronic charge, k=1.38^-23joule k=boltzmann constant and T-temp. in K if the saturation current I. is 1ηA, cal the forward and reverse resistances at V=0.2 and T=300K[/FONT] Thanks a lot.
I'm going to assume that V(reverse) = -V(forward) = -0.2 Volts So R(forward) = V(forward)/I(forward) = +0.2/I(forward) R(reverse) = V(reverse)/I(reverse) = -0.2/I(reverse) does that help? By the way is this a germanium diode?
Aren't germanium diodes dead and buried and pushing up daisies????? Or should that be pushing up geraniums????? Just some sick humour. Please forgive me and even ignore me. Sorry. Couldn't resist.
Hi, Just bought some 1N34's - you just never know when they'll come in handy. Might even save an oatmeal box and wind a coil some day.
The small signal equivalent conductance can be found by taking the derivative of the current equation with respect to V. dI.{exp(eV/kT)-1}/dV = I.{exp(eV/kT)}*(e/kT) Just put .2 and -.2 in calculate the conductance and divide into 1 to get resistance. Alternately you could start with V = (kT/e)ln(I/I.+1) and take the derivative with respect to current to get resistance directly.