I'm afraid I have a question that stumps me but most of you could do in your sleep - so I'm hoping you'll indulge an occasional hobbyist with minimal experience and no theory training!
I'm modifying a "universal" motor (this one) so that it will reverse direction, for use driving my watchmaker's lathe (I'm a clockmaker/watchmaker). It's a DC motor with an internally-mounted bridge diode allowing it to run from the wall AC outlet. I am basically following the attached diagram for wiring. I removed & replaced the bridge diode externally in a separate enclosure alongside a DPDT center-off toggle switch so I can reverse polarity to the motor's brushes. I managed to burn out the original bridge diode, and I replaced it with this one.
MY QUESTION: I want to add a bi-color 2-wire LED (this one) to the circuit just to glow different colors depending on the motor's spin direction.
So how do I hook up the LED in the circuit? I know I need a resistor to achieve a voltage drop so I don't burn the LED (the bridge diode puts out 110 VDC and the LED only needs 2 VDC) but that's as much as I know.
I need to know the following:
1. What value for the resistor (ohms and watt-rating)?
2. Should the resistor be wired in series or parallel with the LED?
3. Should the resulting LED/resistor pair be placed in series or parallel with the motor's brushes?
Maybe the LED/resistor pair is hooked up some other way, I don't really know. But if someone can just explain in clear descriptive English, I know I can follow directions and accomplish it!
Thanks in advance....
I'm modifying a "universal" motor (this one) so that it will reverse direction, for use driving my watchmaker's lathe (I'm a clockmaker/watchmaker). It's a DC motor with an internally-mounted bridge diode allowing it to run from the wall AC outlet. I am basically following the attached diagram for wiring. I removed & replaced the bridge diode externally in a separate enclosure alongside a DPDT center-off toggle switch so I can reverse polarity to the motor's brushes. I managed to burn out the original bridge diode, and I replaced it with this one.
MY QUESTION: I want to add a bi-color 2-wire LED (this one) to the circuit just to glow different colors depending on the motor's spin direction.
So how do I hook up the LED in the circuit? I know I need a resistor to achieve a voltage drop so I don't burn the LED (the bridge diode puts out 110 VDC and the LED only needs 2 VDC) but that's as much as I know.
I need to know the following:
1. What value for the resistor (ohms and watt-rating)?
2. Should the resistor be wired in series or parallel with the LED?
3. Should the resulting LED/resistor pair be placed in series or parallel with the motor's brushes?
Maybe the LED/resistor pair is hooked up some other way, I don't really know. But if someone can just explain in clear descriptive English, I know I can follow directions and accomplish it!
Thanks in advance....
Attachments
-
81.3 KB Views: 101