Hi all,
For the past week, I have been trying to get a grasp on the basics of circuitry, but with no luck. I understand OHM's law, and understand how V, I, and R relate to one another mathematically. However, in a practical viewpoint, I just cant seem to wrap my head around this. To clarify my problem, I have an example:
Lets say you have an LED in series with a 3 Volt battery. You dont know how much resistance there is between both ends of the LED, and you dont know the current going through the circuit either. You then add a resistor with a known and constant resistor to this circuit. The light from the LED dims. Is this because by adding the resistance, we are limiting the amount of charge that can pass, (V/R =I), or does it dim because if the voltage drop provided by the resistor(V=IR)?
Additionally, this question is related to the above. If we put four LEDs in series with a battery, will each LED be brighter than the next because of the sum of the voltage drops from the previous LEDs?
Lastly, I've read somewhere that a load only takes the amount of current that it needs. So does that mean that if you have two LEDs that require a different amount of current to run, and you put both in a series with a battery, will the amount of current be equal (because "I" doesn't change with with resistance if they are in a series)? And if so, what effects will there be on the LED that requires less current to run?
As you can see, I am really confused about this. Any feedback would be greatly appreciated.
Thanks,
Sean
For the past week, I have been trying to get a grasp on the basics of circuitry, but with no luck. I understand OHM's law, and understand how V, I, and R relate to one another mathematically. However, in a practical viewpoint, I just cant seem to wrap my head around this. To clarify my problem, I have an example:
Lets say you have an LED in series with a 3 Volt battery. You dont know how much resistance there is between both ends of the LED, and you dont know the current going through the circuit either. You then add a resistor with a known and constant resistor to this circuit. The light from the LED dims. Is this because by adding the resistance, we are limiting the amount of charge that can pass, (V/R =I), or does it dim because if the voltage drop provided by the resistor(V=IR)?
Additionally, this question is related to the above. If we put four LEDs in series with a battery, will each LED be brighter than the next because of the sum of the voltage drops from the previous LEDs?
Lastly, I've read somewhere that a load only takes the amount of current that it needs. So does that mean that if you have two LEDs that require a different amount of current to run, and you put both in a series with a battery, will the amount of current be equal (because "I" doesn't change with with resistance if they are in a series)? And if so, what effects will there be on the LED that requires less current to run?
As you can see, I am really confused about this. Any feedback would be greatly appreciated.
Thanks,
Sean