Hi, I need help with the following problem. A skater does a pirouette at the rate of 2.0 rev / second and then stop within 3/4 rev. Assume that the angular decceleration is constant and calculate its magnitude. I tried to compute it but I found -18 rad/s[sup]2[/sup]. BUt the textbook gives -17 rad/s[sup]2[/sup]. Please can someone help me with this problem? Thank you B
Use the formula v^2 = u^2 + 2as, where v is final velocity (0), u is initial (2rev/sec) a is acceleration, and s is distance (0.75 rev) I get a = -16/6 rev/sec^2 = -16.755 rad/sec^2 This is closer to the text book answer! Martin PS Did you manage to do the question about the spinning reel?