angle of phase

Discussion in 'Homework Help' started by djstar, Apr 27, 2008.

  1. djstar

    Thread Starter Active Member

    Jan 26, 2008
    could some one please give me a helping hand with this . a circuit consists of a 300 Ω resistor in series with a 3H coil and a 5μF capacitor. Determine the tangent of the angle of phase difference between the current and the applied emf when the frequency is

    A) 50Hz
    B) 25Hz

    for the 50Hz circuit i have worked out the impedance as 319 ohms. But not sure if i need this?
  2. mik3

    Senior Member

    Feb 4, 2008
    For 50Hz:

    impedance of L= j942.48 ohm

    impedance of C= -j636.62 ohm

    impedance of R= 300 ohm

    Total impedance =300 + j942.48 - j636.62 =300 + j305.86

    Convert in polar form : 428.43 |__45.55 degrees

    if you assume the voltage to have an angle of 0 degrees then the current will lack the voltage by 45.55 degrees.

    You say to find this 'the tangent of the angle of phase difference' : i guess is the tanget of 45.55 degrees which equals 1.019

    Go on for the 25Hz