I need to set up this circuit, BCD+AB+AC+AD. So what I think is I need 5 AND gates and 3 OR's. I set them up on my breadboard and I'm only getting 4 of the 8 on's.
AB'C'D
AB'CD
ABC'D
ABCD My question, is there a site that explains how to hook up gates proper on a board?

 

You must have done something wrong on your breadboard. Can you post a clear photograph?

 

5 AND gates?

Look at it as A(B+C+D)+BCD

BCD is two of 2 input AND gates or 1 gate with 3 inputs.

(B+C+D) is two 2 input OR gates or 1 gate with 3 inputs.
and 1 AND gate to bring back the A term.

and 1 OR gate to bring

A(B+C+D) + BCD

I count 3 ANDs and 3 ORs or only 2 of each if using 3 input gates.

That is an important reduction because it means one less IC in the circuit.

 

I like this reduction. I'll give it a go. Thanks.