Am I right on this superposition problem?

Discussion in 'Homework Help' started by chaz0426, Apr 4, 2009.

  1. chaz0426

    Thread Starter New Member

    Apr 4, 2009
    if someone wouldn't mind verifying my solution to this problem by superposition?

    It took me a while but I think I got it.

    I used KVL for the voltage source and got -12 -3i -3i = 0 so i' = 2Amps

    for the Current source I used current division and got both currents to equal 1.5Amps so i'' = 1.5Amps going the other direction

    When adding them both together since i'' was going the other way against i' yielded i'-i'' = 0.5 Amps flowing to the right. so i = 0.5 A. Is that right? I can't see why not but I spent so much time and confusion I can never be sure. Is it right?
  2. vvkannan

    Active Member

    Aug 9, 2008
    Hello chaz0426,
    Yes you are right
  3. magicChristian

    New Member

    Nov 20, 2016
    arly an ideal current source Hi chaz0426
    I think on the voltages source as well on the current source you need to have the resistance
    too. If you suggest a ideal votlage source the resistance would be 0 and there is always
    12 V on it. Similarly the current source would deliver the current of 3 A at any voltage across.
    First the 6 Ohm Resistor is just a load to the voltage source.
    The solution is a current of 0,5 A from right to left leading to a voltage of 10.5 V at the
    current source and a current of 3.5 A throug the vertical 3 Ohms.

    Regards Christian