One way is to factor out \(2Aexpi(\omega t + \frac{\phi_{1} + \phi_{2}}{2})\) from the left hand side.How can I show that
\(Aexpi(\omega t - kx + \phi_{1}) + Aexpi(\omega t + kx + \phi_{2}) = 2Aexpi(\omega t + \frac{\phi_{1} + \phi_{2}}{2})cos(kx - \frac{\phi_{1} - \phi_{2}}{2})\)?
by Jake Hertz
by Jake Hertz
by Aaron Carman