AC Using KVL for RL

Discussion in 'Homework Help' started by davonecuts, Sep 5, 2009.

  1. davonecuts

    Thread Starter New Member

    Sep 5, 2009
    I have been working on this for 2 days Ive tried to do it in polar form and rectangular The loop equation is VmCos(wt-0)=RImSin(wt)+wLImCos(wt)
    When i add them up of course the equal Vm but the problem ask to sovle for VLmax and Vrmax I can use Vin VR + VL but how do u do it with The first loop I presented the givens are R 1000 ohms F=2000hz Vmax =10v L=100mH
    So far i think its Vm/IM=RI+wl
    Vrmax6.2v Vlmax 7.8v Imax 6.2ma
  2. Ratch

    New Member

    Mar 20, 2007

    Looks to me like you got the right answers. What is the problem?

    ω=2∏f = 12566, Xl = jωL = j1257, Z = 1000 + j1257 = 1606/_51.5 , Im = 10/(1606/_51.5) =0.00623/_-51.5 , Vrmax = 1000*Im = 6.23/_-51.5 volts, Vlmax = j1257*Im = 7.83/_38.5 .

  3. davonecuts

    Thread Starter New Member

    Sep 5, 2009
    The answers didnt add up to multisim values because they were in RMS. You could also calculate the values in Polar or Rectangular form but they wont work with out a degree or imaginary number.The question wanted the answers with out the phase diff so you would just use Sqrt of x ^2 + y^2 . Duhhh