# AC analysis - Average Power, Conservation of Power

Discussion in 'Homework Help' started by jegues, Dec 2, 2010.

1. ### jegues Thread Starter Well-Known Member

Sep 13, 2010
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See figure attached for problem statement as well as my work.

I found the currents $i_{1},i_{2}$ then I calculated the average power of each element.

It says to investigate the conservation of power.

Now I have the source delivering 500W of average power and the elements dissapating 400W of average power.

Am I suppose to be able to conclude that the average power supplied and the average power dissipated is the same? If so, where did I make my mistake? What am I misunderstanding?

The formula I used to solve the average power was,

$P_{n} = \frac{I_{m}^{2}}{2} \cdot Re(Z)$

EDIT: I found my mistake, for the source I'm suppose to take the equvalent impeadance at the terminals of the source for the calculation of the average power.

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• ###### AVPA1P2.JPG
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Last edited: Dec 3, 2010