a question regarding this article


Joined Jan 28, 2005
If you temporarily remove the 2 Ohm resistor from the circuit, you will end up with a total voltage across R1 and R3 of 21 volts (28V - 7V). The total resistance in the loop is 5 ohms. Ohm's Law permits you to calculate the current in the loop by dividing 21 by 5. The current is 4.2 Amps. Next, mulitply 4 Ohms times 4.2 Amps and you get 16.8 volts dropped across R1. Subtract 16.8 Volts from 28 Volts and you get 11.2 Volts. This is where the 11.2 volts comes from.

Last edited: