I am having trouble trying to understand this capacitance ratio equation for varactor diodes. I think I have figured some of it out like the \(C_2_0\) means the capacitance of the varactor diode at 20 reverse voltage. Now am now trying to figure out CR (Capacitance ratio)... for each volt increase how much exactly does the capacitance decrease.
\(C_2_0=\frac{C_2}{CR}=\frac{22pF}{5}\)
I interpret this equation as What is the varactor capacitance at 20 reverse voltage if the capacitance at 2 reverse voltage is equal to 22 pico farads using a varactor capacitance ratio of 5.
....
\(\frac{22pF}{4.4pF}=\frac{C_2_0}{C_2}\)
\(\frac{20V}{4.4pF}=\frac{2V}{22pF}\)
\(\frac{22/22}{4.4/22}=\frac{1}{.2}=5\)
This does not add up in a linear fashion, how would I go about creating the equation for the graph of capacitance vs reverse voltage.
\(C_2_0=\frac{C_2}{CR}=\frac{22pF}{5}\)
I interpret this equation as What is the varactor capacitance at 20 reverse voltage if the capacitance at 2 reverse voltage is equal to 22 pico farads using a varactor capacitance ratio of 5.
....
\(\frac{22pF}{4.4pF}=\frac{C_2_0}{C_2}\)
\(\frac{20V}{4.4pF}=\frac{2V}{22pF}\)
\(\frac{22/22}{4.4/22}=\frac{1}{.2}=5\)
This does not add up in a linear fashion, how would I go about creating the equation for the graph of capacitance vs reverse voltage.
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