A Derivation w.r.t AC Signal

Thread Starter

imfaizzi

Joined Oct 11, 2008
20
hi,

can anyone gimme the Solved derivation (or its link/pdf/anything) for the following equation.

Rich (BB code):
__
RE = 25mV
    IE


Also, what is RE and IE anyway?
 

mik3

Joined Feb 4, 2008
4,843
Re is the impedance looking into the emitter of the transistor and Ie is the DC bias current flowing through the emitter.
 

mik3

Joined Feb 4, 2008
4,843
Use the diode equation

I=Io*((expV/VT)-1)

and find dV/dI to get Re

dI/dV=(Io*exp(V/VT))/VT

but Io*exp(V/VT)=I+Io

thus dI/dV=(Io+I)/VT, because Io is very small we ignore it and we get

dI/dV=I/VT

but Re=dV/dI=VT/I=25mV/I, because VT equals about 25mV at room temperature.
 
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